In a certain question managed to get to:
R*(dQ/dt) + (1/C)*Q = 0
In the answers it then says:
Q(t) = Q*e^-(t/RC)
I know this is true, obviously, but don't understand the jump between the two steps, does he integrate it, how?
Cheers!
Circuit equation proof?
SORRY I FORGET TO intergrate from Q0 to Q!!
subtract (1/c)Q on the other side
R(dQ/dt)=-Q/C
its a separable differential equation so you need the Q on the other side.
R(dQ/Q)(1/dt)=-1/C
(dQ/Q)(1/dt)=-1/RC
dQ/Q=-dt/RC
intergrate dQ from Q0 to Q and
intergrate dt from 0 to t so
lnQ/Q0=-t/RC
take the e on both sides
Q=Q0e^(-t/RC)
Q is a function of time so
Q(t)=Q0e^(-t/RC)
SORRY I FORGET TO intergrate from Q0 to Q!!
if you need any more help just ask.
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