Managed the rest of the sheet I was given, but this question has completely stumped me - any help would be much appreciated :)
"Amyl nitrate (C5H11NO2) is a vasodilator. A research student found a method for making this compound on the internet. Some of the details were downloaded and are given below.
Dissolve 14.5g of potassium nitrate (KNO2) in 8ml of water and in a separate vessel mix 15g(18ml) of amyl alcohol C5H11OH with 30g of concentrated sulphuric acid. Cool the latter and add it slowly to the solution of the nitrite with stirring.
C5H11OH + KNO2 + H2SO4 --%26gt; C5H11NO2 + H2O + KHSO4
a) Which reactant or reactants is or are in excess?
b) If the student used the method above, calculate the maximum amount of amyl nitrite formed. Assume the reaction goes to completion.
c) The student successfully followed the method above and managed to make 12g of the product. Calculate the percentage yeild of amyl nitrite obtained in the preparation."
Thanks
Chemistry help - Reacting Masses?
It is basically all about molecular weights.
C5H11NO2 = 117g/mole
KNO2 = 85 g/mole
C5H11OH = 88g/mole
H2SO4 =98 g/mole
H2O = 18g/mole
KHSO4 = 136 g/mole
a) You have to work out the number of moles of each reactant you have.
KNO2 = 14.5g/ 85g/mole = 0.17moles
C5H11OH = 15g/88g/mole = 0.17moles
H2SO4 = 30g / 98 g/mole = 0.30 moles
Sulphuric acid in excess as there are extra moles.
b) As you use 0.17moles of reactants, you get 0.17moles of each of the products.
C5H11NO2 = 0.17 moles = 0.17 * 117g/mole = 19.89 g
c) 12g / 19.89g * 100% = 60% yield
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